text/basic_properties.tex
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%!TEX root = ../blob1.tex
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\subsection{Basic properties}
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\label{sec:basic-properties}
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In this section we complete the proofs of Properties \ref{property:disjoint-union}--\ref{property:contractibility}.
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Throughout the paper, where possible, we prove results using Properties \ref{property:functoriality}--\ref{property:contractibility}, 
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rather than the actual definition of the blob complex.
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This allows the possibility of future improvements on or alternatives to our definition.
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In fact, we hope that there may be a characterization of the blob complex in 
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terms of Properties \ref{property:functoriality}--\ref{property:contractibility}, but at this point we are unaware of one.
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Recall Property \ref{property:disjoint-union}, 
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that there is a natural isomorphism $\bc_*(X \du Y) \cong \bc_*(X) \otimes \bc_*(Y)$.
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\begin{proof}[Proof of Property \ref{property:disjoint-union}]
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Given blob diagrams $b_1$ on $X$ and $b_2$ on $Y$, we can combine them
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(putting the $b_1$ blobs before the $b_2$ blobs in the ordering) to get a
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blob diagram $(b_1, b_2)$ on $X \du Y$.
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Because of the blob reordering relations, all blob diagrams on $X \du Y$ arise this way.
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In the other direction, any blob diagram on $X\du Y$ is equal (up to sign)
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to one that puts $X$ blobs before $Y$ blobs in the ordering, and so determines
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a pair of blob diagrams on $X$ and $Y$.
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These two maps are compatible with our sign conventions.
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(We follow the usual convention for tensors products of complexes, 
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as in e.g. \cite{MR1438306}: $d(a \tensor b) = da \tensor b + (-1)^{\deg(a)} a \tensor db$.)
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The two maps are inverses of each other.
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\end{proof}
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For the next proposition we will temporarily restore $n$-manifold boundary
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conditions to the notation.
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Suppose that for all $c \in \cC(\bd B^n)$
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we have a splitting $s: H_0(\bc_*(B^n; c)) \to \bc_0(B^n; c)$
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of the quotient map
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$p: \bc_0(B^n; c) \to H_0(\bc_*(B^n; c))$.
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For example, this is always the case if the coefficient ring is a field.
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Then
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\begin{prop} \label{bcontract}
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For all $c \in \cC(\bd B^n)$ the natural map $p: \bc_*(B^n; c) \to H_0(\bc_*(B^n; c))$
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is a chain homotopy equivalence
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with inverse $s: H_0(\bc_*(B^n; c)) \to \bc_*(B^n; c)$.
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Here we think of $H_0(\bc_*(B^n; c))$ as a 1-step complex concentrated in degree 0.
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\end{prop}
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\begin{proof}
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By assumption $p\circ s = \id$, so all that remains is to find a degree 1 map
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$h : \bc_*(B^n; c) \to \bc_*(B^n; c)$ such that $\bd h + h\bd = \id - s \circ p$.
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For $i \ge 1$, define $h_i : \bc_i(B^n; c) \to \bc_{i+1}(B^n; c)$ by adding
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an $(i{+}1)$-st blob equal to all of $B^n$.
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In other words, add a new outermost blob which encloses all of the others.
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Define $h_0 : \bc_0(B^n; c) \to \bc_1(B^n; c)$ by setting $h_0(x)$ equal to
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the 1-blob with blob $B^n$ and label $x - s(p(x)) \in U(B^n; c)$.
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\end{proof}
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This proves Property \ref{property:contractibility} (the second half of the 
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statement of this Property was immediate from the definitions).
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Note that even when there is no splitting $s$, we can let $h_0 = 0$ and get a homotopy
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equivalence to the 2-step complex $U(B^n; c) \to \cC(B^n; c)$.
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For fields based on $n$-categories, $H_0(\bc_*(B^n; c)) \cong \mor(c', c'')$,
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where $(c', c'')$ is some (any) splitting of $c$ into domain and range.
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\begin{cor} \label{disj-union-contract}
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If $X$ is a disjoint union of $n$-balls, then $\bc_*(X; c)$ is contractible.
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\end{cor}
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\begin{proof}
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This follows from Properties \ref{property:disjoint-union} and \ref{property:contractibility}.
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\end{proof}
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%Recall the definition of the support of a blob diagram as the union of all the 
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%blobs of the diagram.
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We define the {\it support} of a blob diagram $b$, $\supp(b) \sub X$, 
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to be the union of the blobs of $b$.
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For $y \in \bc_*(X)$ with $y = \sum c_i b_i$ ($c_i$ a non-zero number, $b_i$ a blob diagram),
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we define $\supp(y) \deq \bigcup_i \supp(b_i)$.
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%%%%% the following is true in spirit, but technically incorrect if blobs are not embedded; 
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%%%%% we only use this once, so move lemma and proof to Hochschild section
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\noop{ %%%%%%%%%% begin \noop
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For future use we prove the following lemma.
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\begin{lemma} \label{support-shrink}
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Let $L_* \sub \bc_*(X)$ be a subcomplex generated by some
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subset of the blob diagrams on $X$, and let $f: L_* \to L_*$
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be a chain map which does not increase supports and which induces an isomorphism on
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$H_0(L_*)$.
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Then $f$ is homotopic (in $\bc_*(X)$) to the identity $L_*\to L_*$.
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\end{lemma}
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\begin{proof}
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We will use the method of acyclic models.
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Let $b$ be a blob diagram of $L_*$, let $S\sub X$ be the support of $b$, and let
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$r$ be the restriction of $b$ to $X\setminus S$.
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Note that $S$ is a disjoint union of balls.
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Assign to $b$ the acyclic (in positive degrees) subcomplex $T(b) \deq r\bullet\bc_*(S)$.
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Note that if a diagram $b'$ is part of $\bd b$ then $T(b') \sub T(b)$.
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Both $f$ and the identity are compatible with $T$ (in the sense of acyclic models, \S\ref{sec:moam}), 
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so $f$ and the identity map are homotopic.
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\end{proof}
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} %%%%%%%%%%%%% end \noop
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For the next proposition we will temporarily restore $n$-manifold boundary
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conditions to the notation. Let $X$ be an $n$-manifold, with $\bd X = Y \cup Y \cup Z$.
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Gluing the two copies of $Y$ together yields an $n$-manifold $X\sgl$
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with boundary $Z\sgl$.
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Given compatible fields (boundary conditions) $a$, $b$ and $c$ on $Y$, $Y$ and $Z$,
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we have the blob complex $\bc_*(X; a, b, c)$.
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If $b = a$, then we can glue up blob diagrams on
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$X$ to get blob diagrams on $X\sgl$.
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This proves Property \ref{property:gluing-map}, which we restate here in more detail.
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\begin{prop} \label{blob-gluing}
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There is a natural chain map
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\eq{
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    \gl: \bigoplus_a \bc_*(X; a, a, c) \to \bc_*(X\sgl; c\sgl).
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}
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The sum is over all fields $a$ on $Y$ compatible at their
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($n{-}2$-dimensional) boundaries with $c$.
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``Natural" means natural with respect to the actions of homeomorphisms.
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In degree zero the map agrees with the gluing map coming from the underlying system of fields.
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\end{prop}
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This map is very far from being an isomorphism, even on homology.
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We eliminate this deficit in \S\ref{sec:gluing} below.