text/basic_properties.tex
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     1 %!TEX root = ../blob1.tex
       
     2 
       
     3 \section{Basic properties of the blob complex}
       
     4 \label{sec:basic-properties}
       
     5 
       
     6 \begin{prop} \label{disjunion}
       
     7 There is a natural isomorphism $\bc_*(X \du Y) \cong \bc_*(X) \otimes \bc_*(Y)$.
       
     8 \end{prop}
       
     9 \begin{proof}
       
    10 Given blob diagrams $b_1$ on $X$ and $b_2$ on $Y$, we can combine them
       
    11 (putting the $b_1$ blobs before the $b_2$ blobs in the ordering) to get a
       
    12 blob diagram $(b_1, b_2)$ on $X \du Y$.
       
    13 Because of the blob reordering relations, all blob diagrams on $X \du Y$ arise this way.
       
    14 In the other direction, any blob diagram on $X\du Y$ is equal (up to sign)
       
    15 to one that puts $X$ blobs before $Y$ blobs in the ordering, and so determines
       
    16 a pair of blob diagrams on $X$ and $Y$.
       
    17 These two maps are compatible with our sign conventions.
       
    18 The two maps are inverses of each other.
       
    19 \nn{should probably say something about sign conventions for the differential
       
    20 in a tensor product of chain complexes; ask Scott}
       
    21 \end{proof}
       
    22 
       
    23 For the next proposition we will temporarily restore $n$-manifold boundary
       
    24 conditions to the notation.
       
    25 
       
    26 Suppose that for all $c \in \cC(\bd B^n)$
       
    27 we have a splitting $s: H_0(\bc_*(B^n, c)) \to \bc_0(B^n; c)$
       
    28 of the quotient map
       
    29 $p: \bc_0(B^n; c) \to H_0(\bc_*(B^n, c))$.
       
    30 For example, this is always the case if you coefficient ring is a field.
       
    31 Then
       
    32 \begin{prop} \label{bcontract}
       
    33 For all $c \in \cC(\bd B^n)$ the natural map $p: \bc_*(B^n, c) \to H_0(\bc_*(B^n, c))$
       
    34 is a chain homotopy equivalence
       
    35 with inverse $s: H_0(\bc_*(B^n, c)) \to \bc_*(B^n; c)$.
       
    36 Here we think of $H_0(\bc_*(B^n, c))$ as a 1-step complex concentrated in degree 0.
       
    37 \end{prop}
       
    38 \begin{proof}
       
    39 By assumption $p\circ s = \id$, so all that remains is to find a degree 1 map
       
    40 $h : \bc_*(B^n; c) \to \bc_*(B^n; c)$ such that $\bd h + h\bd = \id - s \circ p$.
       
    41 For $i \ge 1$, define $h_i : \bc_i(B^n; c) \to \bc_{i+1}(B^n; c)$ by adding
       
    42 an $(i{+}1)$-st blob equal to all of $B^n$.
       
    43 In other words, add a new outermost blob which encloses all of the others.
       
    44 Define $h_0 : \bc_0(B^n; c) \to \bc_1(B^n; c)$ by setting $h_0(x)$ equal to
       
    45 the 1-blob with blob $B^n$ and label $x - s(p(x)) \in U(B^n; c)$.
       
    46 \end{proof}
       
    47 
       
    48 Note that if there is no splitting $s$, we can let $h_0 = 0$ and get a homotopy
       
    49 equivalence to the 2-step complex $U(B^n; c) \to \cC(B^n; c)$.
       
    50 
       
    51 For fields based on $n$-categories, $H_0(\bc_*(B^n; c)) \cong \mor(c', c'')$,
       
    52 where $(c', c'')$ is some (any) splitting of $c$ into domain and range.
       
    53 
       
    54 \medskip
       
    55 
       
    56 \nn{Maybe there is no longer a need to repeat the next couple of props here, since we also state them in the introduction.
       
    57 But I think it's worth saying that the Diff actions will be enhanced later.
       
    58 Maybe put that in the intro too.}
       
    59 
       
    60 As we noted above,
       
    61 \begin{prop}
       
    62 There is a natural isomorphism $H_0(\bc_*(X)) \cong A(X)$.
       
    63 \qed
       
    64 \end{prop}
       
    65 
       
    66 
       
    67 \begin{prop}
       
    68 For fixed fields ($n$-cat), $\bc_*$ is a functor from the category
       
    69 of $n$-manifolds and diffeomorphisms to the category of chain complexes and
       
    70 (chain map) isomorphisms.
       
    71 \qed
       
    72 \end{prop}
       
    73 
       
    74 In particular,
       
    75 \begin{prop}  \label{diff0prop}
       
    76 There is an action of $\Diff(X)$ on $\bc_*(X)$.
       
    77 \qed
       
    78 \end{prop}
       
    79 
       
    80 The above will be greatly strengthened in Section \ref{sec:evaluation}.
       
    81 
       
    82 \medskip
       
    83 
       
    84 For the next proposition we will temporarily restore $n$-manifold boundary
       
    85 conditions to the notation.
       
    86 
       
    87 Let $X$ be an $n$-manifold, $\bd X = Y \cup (-Y) \cup Z$.
       
    88 Gluing the two copies of $Y$ together yields an $n$-manifold $X\sgl$
       
    89 with boundary $Z\sgl$.
       
    90 Given compatible fields (boundary conditions) $a$, $b$ and $c$ on $Y$, $-Y$ and $Z$,
       
    91 we have the blob complex $\bc_*(X; a, b, c)$.
       
    92 If $b = -a$ (the orientation reversal of $a$), then we can glue up blob diagrams on
       
    93 $X$ to get blob diagrams on $X\sgl$:
       
    94 
       
    95 \begin{prop}
       
    96 There is a natural chain map
       
    97 \eq{
       
    98     \gl: \bigoplus_a \bc_*(X; a, -a, c) \to \bc_*(X\sgl; c\sgl).
       
    99 }
       
   100 The sum is over all fields $a$ on $Y$ compatible at their
       
   101 ($n{-}2$-dimensional) boundaries with $c$.
       
   102 `Natural' means natural with respect to the actions of diffeomorphisms.
       
   103 \qed
       
   104 \end{prop}
       
   105 
       
   106 The above map is very far from being an isomorphism, even on homology.
       
   107 This will be fixed in Section \ref{sec:gluing} below.
       
   108 
       
   109 \nn{Next para not need, since we already use bullet = gluing notation above(?)}
       
   110 
       
   111 An instance of gluing we will encounter frequently below is where $X = X_1 \du X_2$
       
   112 and $X\sgl = X_1 \cup_Y X_2$.
       
   113 (Typically one of $X_1$ or $X_2$ is a disjoint union of balls.)
       
   114 For $x_i \in \bc_*(X_i)$, we introduce the notation
       
   115 \eq{
       
   116     x_1 \bullet x_2 \deq \gl(x_1 \otimes x_2) .
       
   117 }
       
   118 Note that we have resumed our habit of omitting boundary labels from the notation.
       
   119 
       
   120 
       
   121