Automated merge with https://tqft.net/hg/blob/
authorKevin Walker <kevin@canyon23.net>
Mon, 04 Jul 2011 10:26:37 -0600
changeset 846 40b2a6d891c6
parent 844 002b4838cc34 (diff)
parent 845 c9b55efd79dd (current diff)
child 847 50088eefeedf
Automated merge with https://tqft.net/hg/blob/
--- a/text/blobdef.tex	Mon Jul 04 10:25:42 2011 -0600
+++ b/text/blobdef.tex	Mon Jul 04 10:26:37 2011 -0600
@@ -163,8 +163,8 @@
 \begin{align*}
 A & = [0,1] \times [0,1] \times [0,1] \\
 B & = [0,1] \times [-1,0] \times [0,1] \\
-C & = [-1,0] \times \setc{(y,z)}{z \sin(1/z) \leq y \leq 1, z \in [0,1]} \\
-D & = [-1,0] \times \setc{(y,z)}{-1 \leq y \leq z \sin(1/z), z \in [0,1]}.
+C & = [-1,0] \times \setc{(y,z)}{e^{-1/z^2} \sin(1/z) \leq y \leq 1, z \in [0,1]} \\
+D & = [-1,0] \times \setc{(y,z)}{-1 \leq y \leq e^{-1/z^2} \sin(1/z), z \in [0,1]}.
 \end{align*}
 Here $A \cup B = [0,1] \times [-1,1] \times [0,1]$ and $C \cup D = [-1,0] \times [-1,1] \times [0,1]$. 
 Now, $\{A\}$ is a valid configuration of blobs in $A \cup B$,