author | scott@6e1638ff-ae45-0410-89bd-df963105f760 |
Tue, 27 Oct 2009 02:11:36 +0000 | |
changeset 136 | 77a311b5e2df |
parent 100 | c5a43be00ed4 |
child 140 | e0b304e6b975 |
permissions | -rw-r--r-- |
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%!TEX root = ../blob1.tex |
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\section{Hochschild homology when $n=1$} |
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\label{sec:hochschild} |
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In this section we analyze the blob complex in dimension $n=1$ |
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and find that for $S^1$ the blob complex is homotopy equivalent to the |
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Hochschild complex of the category (algebroid) that we started with. |
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\nn{need to be consistent about quasi-isomorphic versus homotopy equivalent |
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in this section. |
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since the various complexes are free, q.i. implies h.e.} |
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Let $C$ be a *-1-category. |
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Then specializing the definitions from above to the case $n=1$ we have: |
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\begin{itemize} |
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\item $\cC(pt) = \ob(C)$ . |
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\item Let $R$ be a 1-manifold and $c \in \cC(\bd R)$. |
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Then an element of $\cC(R; c)$ is a collection of (transversely oriented) |
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points in the interior |
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of $R$, each labeled by a morphism of $C$. |
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The intervals between the points are labeled by objects of $C$, consistent with |
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the boundary condition $c$ and the domains and ranges of the point labels. |
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\item There is an evaluation map $e: \cC(I; a, b) \to \mor(a, b)$ given by |
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composing the morphism labels of the points. |
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Note that we also need the * of *-1-category here in order to make all the morphisms point |
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the same way. |
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\item For $x \in \mor(a, b)$ let $\chi(x) \in \cC(I; a, b)$ be the field with a single |
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point (at some standard location) labeled by $x$. |
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Then the kernel of the evaluation map $U(I; a, b)$ is generated by things of the |
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form $y - \chi(e(y))$. |
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Thus we can, if we choose, restrict the blob twig labels to things of this form. |
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\end{itemize} |
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We want to show that $\bc_*(S^1)$ is homotopy equivalent to the |
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Hochschild complex of $C$. |
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Note that both complexes are free (and hence projective), so it suffices to show that they |
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are quasi-isomorphic. |
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In order to prove this we will need to extend the blob complex to allow points to also |
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be labeled by elements of $C$-$C$-bimodules. |
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Fix points $p_1, \ldots, p_k \in S^1$ and $C$-$C$-bimodules $M_1, \ldots M_k$. |
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We define a blob-like complex $K_*(S^1, (p_i), (M_i))$. |
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The fields have elements of $M_i$ labeling $p_i$ and elements of $C$ labeling |
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other points. |
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The blob twig labels lie in kernels of evaluation maps. |
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(The range of these evaluation maps is a tensor product (over $C$) of $M_i$'s.) |
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Let $K_*(M) = K_*(S^1, (*), (M))$, where $* \in S^1$ is some standard base point. |
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In other words, fields for $K_*(M)$ have an element of $M$ at the fixed point $*$ |
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and elements of $C$ at variable other points. |
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We claim that |
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\begin{thm} \label{hochthm} |
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The blob complex $\bc_*(S^1; C)$ on the circle is quasi-isomorphic to the |
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usual Hochschild complex for $C$. |
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\end{thm} |
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This follows from two results. First, we see that |
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\begin{lem} |
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\label{lem:module-blob}% |
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The complex $K_*(C)$ (here $C$ is being thought of as a |
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$C$-$C$-bimodule, not a category) is homotopy equivalent to the blob complex |
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$\bc_*(S^1; C)$. (Proof later.) |
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\end{lem} |
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Next, we show that for any $C$-$C$-bimodule $M$, |
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\begin{prop} \label{prop:hoch} |
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The complex $K_*(M)$ is quasi-isomorphic to $\HC_*(M)$, the usual |
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Hochschild complex of $M$. |
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\end{prop} |
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\begin{proof} |
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Recall that the usual Hochschild complex of $M$ is uniquely determined, |
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up to quasi-isomorphism, by the following properties: |
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\begin{enumerate} |
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\item \label{item:hochschild-additive}% |
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$\HC_*(M_1 \oplus M_2) \cong \HC_*(M_1) \oplus \HC_*(M_2)$. |
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\item \label{item:hochschild-exact}% |
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An exact sequence $0 \to M_1 \into M_2 \onto M_3 \to 0$ gives rise to an |
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exact sequence $0 \to \HC_*(M_1) \into \HC_*(M_2) \onto \HC_*(M_3) \to 0$. |
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\item \label{item:hochschild-coinvariants}% |
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$\HH_0(M)$ is isomorphic to the coinvariants of $M$, $\coinv(M) = |
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M/\langle cm-mc \rangle$. |
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\item \label{item:hochschild-free}% |
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$\HC_*(C\otimes C)$ is contractible. |
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(Here $C\otimes C$ denotes |
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the free $C$-$C$-bimodule with one generator.) |
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That is, $\HC_*(C\otimes C)$ is |
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quasi-isomorphic to its $0$-th homology (which in turn, by \ref{item:hochschild-coinvariants}, is just $C$) via the quotient map $\HC_0 \onto \HH_0$. |
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\end{enumerate} |
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(Together, these just say that Hochschild homology is `the derived functor of coinvariants'.) |
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We'll first recall why these properties are characteristic. |
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Take some $C$-$C$ bimodule $M$, and choose a free resolution |
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\begin{equation*} |
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\cdots \to F_2 \xrightarrow{f_2} F_1 \xrightarrow{f_1} F_0. |
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\end{equation*} |
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We will show that for any functor $\cP$ satisfying properties |
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\ref{item:hochschild-additive}, \ref{item:hochschild-exact}, |
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\ref{item:hochschild-coinvariants} and \ref{item:hochschild-free}, there |
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is a quasi-isomorphism |
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102 |
$$\cP_*(M) \iso \coinv(F_*).$$ |
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103 |
% |
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104 |
Observe that there's a quotient map $\pi: F_0 \onto M$, and by |
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105 |
construction the cone of the chain map $\pi: F_* \to M$ is acyclic. Now |
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106 |
construct the total complex $\cP_i(F_j)$, with $i,j \geq 0$, graded by |
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107 |
$i+j$. We have two chain maps |
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108 |
\begin{align*} |
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109 |
\cP_i(F_*) & \xrightarrow{\cP_i(\pi)} \cP_i(M) \\ |
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110 |
\intertext{and} |
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111 |
\cP_*(F_j) & \xrightarrow{\cP_0(F_j) \onto H_0(\cP_*(F_j))} \coinv(F_j). |
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112 |
\end{align*} |
136 | 113 |
The cone of each chain map is acyclic. In the first case, this is because the `rows' indexed by $i$ are acyclic since $\HC_i$ is exact. |
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114 |
In the second case, this is because the `columns' indexed by $j$ are acyclic, since $F_j$ is free. |
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115 |
Because the cones are acyclic, the chain maps are quasi-isomorphisms. Composing one with the inverse of the other, we obtain the desired quasi-isomorphism |
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116 |
$$\cP_*(M) \quismto \coinv(F_*).$$ |
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117 |
|
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118 |
%If $M$ is free, that is, a direct sum of copies of |
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119 |
%$C \tensor C$, then properties \ref{item:hochschild-additive} and |
136 | 120 |
%\ref{item:hochschild-free} determine $\HC_*(M)$. Otherwise, choose some |
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121 |
%free cover $F \onto M$, and define $K$ to be this map's kernel. Thus we |
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122 |
%have a short exact sequence $0 \to K \into F \onto M \to 0$, and hence a |
136 | 123 |
%short exact sequence of complexes $0 \to \HC_*(K) \into \HC_*(F) \onto \HC_*(M) |
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124 |
%\to 0$. Such a sequence gives a long exact sequence on homology |
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125 |
%\begin{equation*} |
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126 |
%%\begin{split} |
136 | 127 |
%\cdots \to \HH_{i+1}(F) \to \HH_{i+1}(M) \to \HH_i(K) \to \HH_i(F) \to \cdots % \\ |
128 |
%%\cdots \to \HH_1(F) \to \HH_1(M) \to \HH_0(K) \to \HH_0(F) \to \HH_0(M). |
|
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129 |
%%\end{split} |
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130 |
%\end{equation*} |
136 | 131 |
%For any $i \geq 1$, $\HH_{i+1}(F) = \HH_i(F) = 0$, by properties |
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132 |
%\ref{item:hochschild-additive} and \ref{item:hochschild-free}, and so |
136 | 133 |
%$\HH_{i+1}(M) \iso \HH_i(F)$. For $i=0$, \todo{}. |
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134 |
% |
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135 |
%This tells us how to |
136 | 136 |
%compute every homology group of $\HC_*(M)$; we already know $\HH_0(M)$ |
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137 |
%(it's just coinvariants, by property \ref{item:hochschild-coinvariants}), |
136 | 138 |
%and higher homology groups are determined by lower ones in $\HC_*(K)$, and |
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139 |
%hence recursively as coinvariants of some other bimodule. |
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140 |
|
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141 |
Proposition \ref{prop:hoch} then follows from the following lemmas, establishing that $K_*$ has precisely these required properties. |
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142 |
\begin{lem} |
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143 |
\label{lem:hochschild-additive}% |
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144 |
Directly from the definition, $K_*(M_1 \oplus M_2) \cong K_*(M_1) \oplus K_*(M_2)$. |
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145 |
\end{lem} |
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146 |
\begin{lem} |
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147 |
\label{lem:hochschild-exact}% |
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148 |
An exact sequence $0 \to M_1 \into M_2 \onto M_3 \to 0$ gives rise to an |
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149 |
exact sequence $0 \to K_*(M_1) \into K_*(M_2) \onto K_*(M_3) \to 0$. |
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150 |
\end{lem} |
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151 |
\begin{lem} |
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152 |
\label{lem:hochschild-coinvariants}% |
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153 |
$H_0(K_*(M))$ is isomorphic to the coinvariants of $M$. |
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154 |
\end{lem} |
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155 |
\begin{lem} |
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156 |
\label{lem:hochschild-free}% |
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157 |
$K_*(C\otimes C)$ is quasi-isomorphic to $H_0(K_*(C \otimes C)) \iso C$. |
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158 |
\end{lem} |
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159 |
|
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160 |
The remainder of this section is devoted to proving Lemmas |
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161 |
\ref{lem:module-blob}, |
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162 |
\ref{lem:hochschild-exact}, \ref{lem:hochschild-coinvariants} and |
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163 |
\ref{lem:hochschild-free}. |
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164 |
\end{proof} |
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165 |
|
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166 |
\begin{proof}[Proof of Lemma \ref{lem:module-blob}] |
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167 |
We show that $K_*(C)$ is quasi-isomorphic to $\bc_*(S^1)$. |
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168 |
$K_*(C)$ differs from $\bc_*(S^1)$ only in that the base point * |
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169 |
is always a labeled point in $K_*(C)$, while in $\bc_*(S^1)$ it may or may not be. |
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170 |
In particular, there is an inclusion map $i: K_*(C) \to \bc_*(S^1)$. |
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171 |
|
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172 |
We define a left inverse $s: \bc_*(S^1) \to K_*(C)$ to the inclusion as follows. |
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173 |
If $y$ is a field defined on a neighborhood of *, define $s(y) = y$ if |
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174 |
* is a labeled point in $y$. |
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175 |
Otherwise, define $s(y)$ to be the result of adding a label 1 (identity morphism) at *. |
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176 |
Extending linearly, we get the desired map $s: \bc_*(S^1) \to K_*(C)$. |
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177 |
%Let $x \in \bc_*(S^1)$. |
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178 |
%Let $s(x)$ be the result of replacing each field $y$ (containing *) mentioned in |
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179 |
%$x$ with $s(y)$. |
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180 |
It is easy to check that $s$ is a chain map and $s \circ i = \id$. |
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181 |
|
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182 |
Let $N_\ep$ denote the ball of radius $\ep$ around *. |
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183 |
Let $L_*^\ep \sub \bc_*(S^1)$ be the subcomplex |
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184 |
spanned by blob diagrams |
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185 |
where there are no labeled points |
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186 |
in $N_\ep$, except perhaps $*$, and $N_\ep$ is either disjoint from or contained in |
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187 |
every blob in the diagram. |
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188 |
Note that for any chain $x \in \bc_*(S^1)$, $x \in L_*^\ep$ for sufficiently small $\ep$. |
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189 |
\nn{what if * is on boundary of a blob? need preliminary homotopy to prevent this.} |
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190 |
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191 |
We define a degree $1$ chain map $j_\ep: L_*^\ep \to L_*^\ep$ as follows. Let $x \in L_*^\ep$ be a blob diagram. |
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192 |
\nn{maybe add figures illustrating $j_\ep$?} |
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193 |
If $*$ is not contained in any twig blob, we define $j_\ep(x)$ by adding $N_\ep$ as a new twig blob, with label $y - s(y)$ where $y$ is the restriction |
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194 |
of $x$ to $N_\ep$. If $*$ is contained in a twig blob $B$ with label $u=\sum z_i$, |
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195 |
write $y_i$ for the restriction of $z_i$ to $N_\ep$, and let |
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196 |
$x_i$ be equal to $x$ on $S^1 \setmin B$, equal to $z_i$ on $B \setmin N_\ep$, |
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197 |
and have an additional blob $N_\ep$ with label $y_i - s(y_i)$. |
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198 |
Define $j_\ep(x) = \sum x_i$. |
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199 |
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200 |
It is not hard to show that on $L_*^\ep$ |
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201 |
\[ |
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\bd j_\ep + j_\ep \bd = \id - i \circ s . |
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\] |
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\nn{need to check signs coming from blob complex differential} |
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Since for $\ep$ small enough $L_*^\ep$ captures all of the |
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homology of $\bc_*(S^1)$, |
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it follows that the mapping cone of $i \circ s$ is acyclic and therefore (using the fact that |
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these complexes are free) $i \circ s$ is homotopic to the identity. |
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\end{proof} |
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|
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\begin{proof}[Proof of Lemma \ref{lem:hochschild-exact}] |
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We now prove that $K_*$ is an exact functor. |
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|
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%\todo{p. 1478 of scott's notes} |
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Essentially, this comes down to the unsurprising fact that the functor on $C$-$C$ bimodules |
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\begin{equation*} |
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M \mapsto \ker(C \tensor M \tensor C \xrightarrow{c_1 \tensor m \tensor c_2 \mapsto c_1 m c_2} M) |
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\end{equation*} |
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is exact. For completeness we'll explain this below. |
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|
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Suppose we have a short exact sequence of $C$-$C$ bimodules $$\xymatrix{0 \ar[r] & K \ar@{^{(}->}[r]^f & E \ar@{->>}[r]^g & Q \ar[r] & 0}.$$ |
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We'll write $\hat{f}$ and $\hat{g}$ for the image of $f$ and $g$ under the functor. |
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Most of what we need to check is easy. |
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If $(a \tensor k \tensor b) \in \ker(C \tensor K \tensor C \to K)$, to have $\hat{f}(a \tensor k \tensor b) = 0 \in \ker(C \tensor E \tensor C \to E)$, we must have $f(k) = 0 \in E$, which implies $k=0$ itself. If $(a \tensor e \tensor b) \in \ker(C \tensor E \tensor C \to E)$ is in the image of $\ker(C \tensor K \tensor C \to K)$ under $\hat{f}$, clearly |
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$e$ is in the image of the original $f$, so is in the kernel of the original $g$, and so $\hat{g}(a \tensor e \tensor b) = 0$. |
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If $\hat{g}(a \tensor e \tensor b) = 0$, then $g(e) = 0$, so $e = f(\widetilde{e})$ for some $\widetilde{e} \in K$, and $a \tensor e \tensor b = \hat{f}(a \tensor \widetilde{e} \tensor b)$. |
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Finally, the interesting step is in checking that any $q = \sum_i a_i \tensor q_i \tensor b_i$ such that $\sum_i a_i q_i b_i = 0$ is in the image of $\ker(C \tensor E \tensor C \to C)$ under $\hat{g}$. |
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For each $i$, we can find $\widetilde{q_i}$ so $g(\widetilde{q_i}) = q_i$. However $\sum_i a_i \widetilde{q_i} b_i$ need not be zero. |
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Consider then $$\widetilde{q} = \sum_i (a_i \tensor \widetilde{q_i} \tensor b_i) - 1 \tensor (\sum_i a_i \widetilde{q_i} b_i) \tensor 1.$$ Certainly |
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$\widetilde{q} \in \ker(C \tensor E \tensor C \to E)$. Further, |
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\begin{align*} |
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\hat{g}(\widetilde{q}) & = \sum_i (a_i \tensor g(\widetilde{q_i}) \tensor b_i) - 1 \tensor (\sum_i a_i g(\widetilde{q_i}) b_i) \tensor 1 \\ |
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& = q - 0 |
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\end{align*} |
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(here we used that $g$ is a map of $C$-$C$ bimodules, and that $\sum_i a_i q_i b_i = 0$). |
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|
69 | 237 |
Similar arguments show that the functors |
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\begin{equation} |
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\label{eq:ker-functor}% |
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M \mapsto \ker(C^{\tensor k} \tensor M \tensor C^{\tensor l} \to M) |
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\end{equation} |
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are all exact too. Moreover, tensor products of such functors with each |
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other and with $C$ or $\ker(C^{\tensor k} \to C)$ (e.g., producing the functor $M \mapsto \ker(M \tensor C \to M) |
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\tensor C \tensor \ker(C \tensor C \to M)$) are all still exact. |
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|
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Finally, then we see that the functor $K_*$ is simply an (infinite) |
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direct sum of copies of this sort of functor. The direct sum is indexed by |
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configurations of nested blobs and of labels; for each such configuration, we have one of the above tensor product functors, |
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with the labels of twig blobs corresponding to tensor factors as in \eqref{eq:ker-functor} or $\ker(C^{\tensor k} \to C)$, and all other labelled points corresponding |
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to tensor factors of $C$. |
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\end{proof} |
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\begin{proof}[Proof of Lemma \ref{lem:hochschild-coinvariants}] |
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We show that $H_0(K_*(M))$ is isomorphic to the coinvariants of $M$. |
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|
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We define a map $\ev: K_0(M) \to M$. If $x \in K_0(M)$ has the label $m \in M$ at $*$, and labels $c_i \in C$ at the other labeled points of $S^1$, reading clockwise from $*$, |
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we set $\ev(x) = m c_1 \cdots c_k$. We can think of this as $\ev : M \tensor C^{\tensor k} \to M$, for each direct summand of $K_0(M)$ indexed by a configuration of labeled points. |
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There is a quotient map $\pi: M \to \coinv{M}$, and the composition $\pi \compose \ev$ is well-defined on the quotient $H_0(K_*(M))$; if $y \in K_1(M)$, the blob in $y$ either contains $*$ or does not. If it doesn't, then |
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suppose $y$ has label $m$ at $*$, labels $c_i$ at other labeled points outside the blob, and the field inside the blob is a sum, with the $j$-th term having |
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labeled points $d_{j,i}$. Then $\sum_j d_{j,1} \tensor \cdots \tensor d_{j,k_j} \in \ker(\DirectSum_k C^{\tensor k} \to C)$, and so |
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$\ev(\bdy y) = 0$, because $$C^{\tensor \ell_1} \tensor \ker(\DirectSum_k C^{\tensor k} \to C) \tensor C^{\tensor \ell_2} \subset \ker(\DirectSum_k C^{\tensor k} \to C).$$ |
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Similarly, if $*$ is contained in the blob, then the blob label is a sum, with the $j$-th term have labelled points $d_{j,i}$ to the left of $*$, $m_j$ at $*$, and $d_{j,i}'$ to the right of $*$, |
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and there are labels $c_i$ at the labeled points outside the blob. We know that |
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$$\sum_j d_{j,1} \tensor \cdots \tensor d_{j,k_j} \tensor m_j \tensor d_{j,1}' \tensor \cdots \tensor d_{j,k'_j}' \in \ker(\DirectSum_{k,k'} C^{\tensor k} \tensor M \tensor C^{\tensor k'} \tensor \to M),$$ |
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and so |
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\begin{align*} |
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\ev(\bdy y) & = \sum_j m_j d_{j,1}' \cdots d_{j,k'_j}' c_1 \cdots c_k d_{j,1} \cdots d_{j,k_j} \\ |
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& = \sum_j d_{j,1} \cdots d_{j,k_j} m_j d_{j,1}' \cdots d_{j,k'_j}' c_1 \cdots c_k \\ |
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& = 0 |
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\end{align*} |
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where this time we use the fact that we're mapping to $\coinv{M}$, not just $M$. |
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|
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The map $\pi \compose \ev: H_0(K_*(M)) \to \coinv{M}$ is clearly surjective ($\ev$ surjects onto $M$); we now show that it's injective. \todo{} |
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\end{proof} |
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\begin{proof}[Proof of Lemma \ref{lem:hochschild-free}] |
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We show that $K_*(C\otimes C)$ is |
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quasi-isomorphic to the 0-step complex $C$. We'll do this in steps, establishing quasi-isomorphisms and homotopy equivalences |
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$$K_*(C \tensor C) \quismto K'_* \htpyto K''_* \quismto C.$$ |
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|
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Let $K'_* \sub K_*(C\otimes C)$ be the subcomplex where the label of |
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the point $*$ is $1 \otimes 1 \in C\otimes C$. |
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We will show that the inclusion $i: K'_* \to K_*(C\otimes C)$ is a quasi-isomorphism. |
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|
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Fix a small $\ep > 0$. |
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Let $N_\ep$ be the ball of radius $\ep$ around $* \in S^1$. |
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Let $K_*^\ep \sub K_*(C\otimes C)$ be the subcomplex |
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generated by blob diagrams $b$ such that $N_\ep$ is either disjoint from |
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or contained in each blob of $b$, and the only labeled point inside $N_\ep$ is $*$. |
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%and the two boundary points of $N_\ep$ are not labeled points of $b$. |
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For a field $y$ on $N_\ep$, let $s_\ep(y)$ be the equivalent picture with~$*$ |
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labeled by $1\otimes 1$ and the only other labeled points at distance $\pm\ep/2$ from $*$. |
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(See Figure \ref{fig:sy}.) Note that $y - s_\ep(y) \in U(N_\ep)$. We can think of |
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$\sigma_\ep$ as a chain map $K_*^\ep \to K_*^\ep$ given by replacing the restriction $y$ to $N_\ep$ of each field |
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appearing in an element of $K_*^\ep$ with $s_\ep(y)$. |
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294 |
Note that $\sigma_\ep(x) \in K'_*$. |
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295 |
\begin{figure}[!ht] |
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296 |
\begin{align*} |
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y & = \mathfig{0.2}{hochschild/y} & |
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s_\ep(y) & = \mathfig{0.2}{hochschild/sy} |
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299 |
\end{align*} |
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\caption{Defining $s_\ep$.} |
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301 |
\label{fig:sy} |
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302 |
\end{figure} |
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303 |
|
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304 |
Define a degree 1 chain map $j_\ep : K_*^\ep \to K_*^\ep$ as follows. |
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305 |
Let $x \in K_*^\ep$ be a blob diagram. |
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If $*$ is not contained in any twig blob, $j_\ep(x)$ is obtained by adding $N_\ep$ to |
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307 |
$x$ as a new twig blob, with label $y - s_\ep(y)$, where $y$ is the restriction of $x$ to $N_\ep$. |
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If $*$ is contained in a twig blob $B$ with label $u = \sum z_i$, $j_\ep(x)$ is obtained as follows. |
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Let $y_i$ be the restriction of $z_i$ to $N_\ep$. |
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Let $x_i$ be equal to $x$ outside of $B$, equal to $z_i$ on $B \setmin N_\ep$, |
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311 |
and have an additional blob $N_\ep$ with label $y_i - s_\ep(y_i)$. |
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312 |
Define $j_\ep(x) = \sum x_i$. |
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313 |
\nn{need to check signs coming from blob complex differential} |
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Note that if $x \in K'_* \cap K_*^\ep$ then $j_\ep(x) \in K'_*$ also. |
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315 |
|
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316 |
The key property of $j_\ep$ is |
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317 |
\eq{ |
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318 |
\bd j_\ep + j_\ep \bd = \id - \sigma_\ep. |
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319 |
} |
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320 |
If $j_\ep$ were defined on all of $K_*(C\otimes C)$, this would show that $\sigma_\ep$ |
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321 |
is a homotopy inverse to the inclusion $K'_* \to K_*(C\otimes C)$. |
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322 |
One strategy would be to try to stitch together various $j_\ep$ for progressively smaller |
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323 |
$\ep$ and show that $K'_*$ is homotopy equivalent to $K_*(C\otimes C)$. |
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324 |
Instead, we'll be less ambitious and just show that |
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325 |
$K'_*$ is quasi-isomorphic to $K_*(C\otimes C)$. |
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326 |
|
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327 |
If $x$ is a cycle in $K_*(C\otimes C)$, then for sufficiently small $\ep$ we have |
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328 |
$x \in K_*^\ep$. |
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329 |
(This is true for any chain in $K_*(C\otimes C)$, since chains are sums of |
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330 |
finitely many blob diagrams.) |
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331 |
Then $x$ is homologous to $s_\ep(x)$, which is in $K'_*$, so the inclusion map |
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332 |
$K'_* \sub K_*(C\otimes C)$ is surjective on homology. |
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333 |
If $y \in K_*(C\otimes C)$ and $\bd y = x \in K'_*$, then $y \in K_*^\ep$ for some $\ep$ |
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334 |
and |
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335 |
\eq{ |
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336 |
\bd y = \bd (\sigma_\ep(y) + j_\ep(x)) . |
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337 |
} |
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338 |
Since $\sigma_\ep(y) + j_\ep(x) \in F'$, it follows that the inclusion map is injective on homology. |
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339 |
This completes the proof that $K'_*$ is quasi-isomorphic to $K_*(C\otimes C)$. |
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340 |
|
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341 |
Let $K''_* \sub K'_*$ be the subcomplex of $K'_*$ where $*$ is not contained in any blob. |
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342 |
We will show that the inclusion $i: K''_* \to K'_*$ is a homotopy equivalence. |
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343 |
|
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344 |
First, a lemma: Let $G''_*$ and $G'_*$ be defined the same as $K''_*$ and $K'_*$, except with |
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345 |
$S^1$ replaced some (any) neighborhood of $* \in S^1$. |
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346 |
Then $G''_*$ and $G'_*$ are both contractible |
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347 |
and the inclusion $G''_* \sub G'_*$ is a homotopy equivalence. |
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348 |
For $G'_*$ the proof is the same as in (\ref{bcontract}), except that the splitting |
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349 |
$G'_0 \to H_0(G'_*)$ concentrates the point labels at two points to the right and left of $*$. |
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350 |
For $G''_*$ we note that any cycle is supported \nn{need to establish terminology for this; maybe |
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351 |
in ``basic properties" section above} away from $*$. |
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352 |
Thus any cycle lies in the image of the normal blob complex of a disjoint union |
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353 |
of two intervals, which is contractible by (\ref{bcontract}) and (\ref{disjunion}). |
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354 |
Actually, we need the further (easy) result that the inclusion |
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355 |
$G''_* \to G'_*$ induces an isomorphism on $H_0$. |
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356 |
|
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357 |
Next we construct a degree 1 map (homotopy) $h: K'_* \to K'_*$ such that |
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358 |
for all $x \in K'_*$ we have |
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359 |
\eq{ |
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360 |
x - \bd h(x) - h(\bd x) \in K''_* . |
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361 |
} |
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362 |
Since $K'_0 = K''_0$, we can take $h_0 = 0$. |
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363 |
Let $x \in K'_1$, with single blob $B \sub S^1$. |
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364 |
If $* \notin B$, then $x \in K''_1$ and we define $h_1(x) = 0$. |
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365 |
If $* \in B$, then we work in the image of $G'_*$ and $G''_*$ (with respect to $B$). |
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366 |
Choose $x'' \in G''_1$ such that $\bd x'' = \bd x$. |
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367 |
Since $G'_*$ is contractible, there exists $y \in G'_2$ such that $\bd y = x - x''$. |
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368 |
Define $h_1(x) = y$. |
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369 |
The general case is similar, except that we have to take lower order homotopies into account. |
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370 |
Let $x \in K'_k$. |
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371 |
If $*$ is not contained in any of the blobs of $x$, then define $h_k(x) = 0$. |
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372 |
Otherwise, let $B$ be the outermost blob of $x$ containing $*$. |
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373 |
By xxxx above, $x = x' \bullet p$, where $x'$ is supported on $B$ and $p$ is supported away from $B$. |
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374 |
So $x' \in G'_l$ for some $l \le k$. |
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375 |
Choose $x'' \in G''_l$ such that $\bd x'' = \bd (x' - h_{l-1}\bd x')$. |
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376 |
Choose $y \in G'_{l+1}$ such that $\bd y = x' - x'' - h_{l-1}\bd x'$. |
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377 |
Define $h_k(x) = y \bullet p$. |
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378 |
This completes the proof that $i: K''_* \to K'_*$ is a homotopy equivalence. |
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379 |
\nn{need to say above more clearly and settle on notation/terminology} |
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380 |
|
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381 |
Finally, we show that $K''_*$ is contractible. |
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382 |
\nn{need to also show that $H_0$ is the right thing; easy, but I won't do it now} |
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383 |
Let $x$ be a cycle in $K''_*$. |
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Q.I => hty equiv for free complexes
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parents:
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|
384 |
The union of the supports of the diagrams in $x$ does not contain $*$, so there exists a |
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Q.I => hty equiv for free complexes
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parents:
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|
385 |
ball $B \subset S^1$ containing the union of the supports and not containing $*$. |
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Q.I => hty equiv for free complexes
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parents:
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changeset
|
386 |
Adding $B$ as a blob to $x$ gives a contraction. |
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Q.I => hty equiv for free complexes
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parents:
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changeset
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387 |
\nn{need to say something else in degree zero} |
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Q.I => hty equiv for free complexes
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parents:
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388 |
\end{proof} |
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|
389 |
|
74 | 390 |
\medskip |
391 |
||
392 |
For purposes of illustration, we describe an explicit chain map |
|
136 | 393 |
$\HC_*(M) \to K_*(M)$ |
74 | 394 |
between the Hochschild complex and the blob complex (with bimodule point) |
395 |
for degree $\le 2$. |
|
396 |
This map can be completed to a homotopy equivalence, though we will not prove that here. |
|
397 |
There are of course many such maps; what we describe here is one of the simpler possibilities. |
|
398 |
Describing the extension to higher degrees is straightforward but tedious. |
|
399 |
\nn{but probably we should include the general case in a future version of this paper} |
|
400 |
||
136 | 401 |
Recall that in low degrees $\HC_*(M)$ is |
74 | 402 |
\[ |
403 |
\cdots \stackrel{\bd}{\to} M \otimes C\otimes C \stackrel{\bd}{\to} |
|
404 |
M \otimes C \stackrel{\bd}{\to} M |
|
405 |
\] |
|
406 |
with |
|
407 |
\eqar{ |
|
408 |
\bd(m\otimes a) & = & ma - am \\ |
|
409 |
\bd(m\otimes a \otimes b) & = & ma\otimes b - m\otimes ab + bm \otimes a . |
|
410 |
} |
|
77 | 411 |
In degree 0, we send $m\in M$ to the 0-blob diagram $\mathfig{0.05}{hochschild/0-chains}$; the base point |
74 | 412 |
in $S^1$ is labeled by $m$ and there are no other labeled points. |
413 |
In degree 1, we send $m\ot a$ to the sum of two 1-blob diagrams |
|
77 | 414 |
as shown in Figure \ref{fig:hochschild-1-chains}. |
415 |
||
416 |
\begin{figure}[!ht] |
|
417 |
\begin{equation*} |
|
418 |
\mathfig{0.4}{hochschild/1-chains} |
|
419 |
\end{equation*} |
|
420 |
\begin{align*} |
|
421 |
u_1 & = \mathfig{0.05}{hochschild/u_1-1} - \mathfig{0.05}{hochschild/u_1-2} & u_2 & = \mathfig{0.05}{hochschild/u_2-1} - \mathfig{0.05}{hochschild/u_2-2} |
|
422 |
\end{align*} |
|
423 |
\caption{The image of $m \tensor a$ in the blob complex.} |
|
424 |
\label{fig:hochschild-1-chains} |
|
425 |
\end{figure} |
|
426 |
||
427 |
In degree 2, we send $m\ot a \ot b$ to the sum of 24 (=6*4) 2-blob diagrams as shown in |
|
428 |
Figure \ref{fig:hochschild-2-chains}. In Figure \ref{fig:hochschild-2-chains} the 1- and 2-blob diagrams are indicated only by their support. |
|
74 | 429 |
We leave it to the reader to determine the labels of the 1-blob diagrams. |
77 | 430 |
\begin{figure}[!ht] |
431 |
\begin{equation*} |
|
432 |
\mathfig{0.6}{hochschild/2-chains-0} |
|
433 |
\end{equation*} |
|
434 |
\begin{equation*} |
|
435 |
\mathfig{0.4}{hochschild/2-chains-1} \qquad \mathfig{0.4}{hochschild/2-chains-2} |
|
436 |
\end{equation*} |
|
437 |
\caption{The 0-, 1- and 2-chains in the image of $m \tensor a \tensor b$. Only the supports of the 1- and 2-blobs are shown.} |
|
438 |
\label{fig:hochschild-2-chains} |
|
439 |
\end{figure} |
|
74 | 440 |
Each 2-cell in the figure is labeled by a ball $V$ in $S^1$ which contains the support of all |
441 |
1-blob diagrams in its boundary. |
|
442 |
Such a 2-cell corresponds to a sum of the 2-blob diagrams obtained by adding $V$ |
|
443 |
as an outer (non-twig) blob to each of the 1-blob diagrams in the boundary of the 2-cell. |
|
77 | 444 |
Figure \ref{fig:hochschild-example-2-cell} shows this explicitly for one of the 2-cells. |
74 | 445 |
Note that the (blob complex) boundary of this sum of 2-blob diagrams is |
446 |
precisely the sum of the 1-blob diagrams corresponding to the boundary of the 2-cell. |
|
447 |
(Compare with the proof of \ref{bcontract}.) |
|
448 |
||
77 | 449 |
\begin{figure}[!ht] |
450 |
\begin{equation*} |
|
451 |
A = \mathfig{0.1}{hochschild/v_1} + \mathfig{0.1}{hochschild/v_2} + \mathfig{0.1}{hochschild/v_3} + \mathfig{0.1}{hochschild/v_4} |
|
452 |
\end{equation*} |
|
453 |
\begin{align*} |
|
454 |
v_1 & = \mathfig{0.05}{hochschild/v_1-1} - \mathfig{0.05}{hochschild/v_1-2} & v_2 & = \mathfig{0.05}{hochschild/v_2-1} - \mathfig{0.05}{hochschild/v_2-2} \\ |
|
455 |
v_3 & = \mathfig{0.05}{hochschild/v_3-1} - \mathfig{0.05}{hochschild/v_3-2} & v_4 & = \mathfig{0.05}{hochschild/v_4-1} - \mathfig{0.05}{hochschild/v_4-2} |
|
456 |
\end{align*} |
|
457 |
\caption{One of the 2-cells from Figure \ref{fig:hochschild-2-chains}.} |
|
458 |
\label{fig:hochschild-example-2-cell} |
|
43
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parents:
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459 |
\end{figure} |