text/hochschild.tex
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    17 
    17 
    18 It is also worth noting that the original idea for the blob complex came from trying
    18 It is also worth noting that the original idea for the blob complex came from trying
    19 to find a more ``local" description of the Hochschild complex.
    19 to find a more ``local" description of the Hochschild complex.
    20 
    20 
    21 Let $C$ be a *-1-category.
    21 Let $C$ be a *-1-category.
    22 Then specializing the definitions from above to the case $n=1$ we have:
    22 Then specializing the definition of the associated system of fields from \S \ref{sec:example:traditional-n-categories(fields)} above to the case $n=1$ we have:
    23 \begin{itemize}
    23 \begin{itemize}
    24 \item $\cC(pt) = \ob(C)$ .
    24 \item $\cC(pt) = \ob(C)$ .
    25 \item Let $R$ be a 1-manifold and $c \in \cC(\bd R)$.
    25 \item Let $R$ be a 1-manifold and $c \in \cC(\bd R)$.
    26 Then an element of $\cC(R; c)$ is a collection of (transversely oriented)
    26 Then an element of $\cC(R; c)$ is a collection of (transversely oriented)
    27 points in the interior
    27 points in the interior
    42 We want to show that $\bc_*(S^1)$ is homotopy equivalent to the
    42 We want to show that $\bc_*(S^1)$ is homotopy equivalent to the
    43 Hochschild complex of $C$.
    43 Hochschild complex of $C$.
    44 In order to prove this we will need to extend the 
    44 In order to prove this we will need to extend the 
    45 definition of the blob complex to allow points to also
    45 definition of the blob complex to allow points to also
    46 be labeled by elements of $C$-$C$-bimodules.
    46 be labeled by elements of $C$-$C$-bimodules.
    47 (See Subsections \ref{moddecss} and \ref{ssec:spherecat} for a more general (i.e.\ $n>1$)
    47 (See Subsections \ref{moddecss} and \ref{ssec:spherecat} for a more general version of this construction that applies in all dimensions.)
    48 version of this construction.)
       
    49 
    48 
    50 Fix points $p_1, \ldots, p_k \in S^1$ and $C$-$C$-bimodules $M_1, \ldots M_k$.
    49 Fix points $p_1, \ldots, p_k \in S^1$ and $C$-$C$-bimodules $M_1, \ldots M_k$.
    51 We define a blob-like complex $K_*(S^1, (p_i), (M_i))$.
    50 We define a blob-like complex $K_*(S^1, (p_i), (M_i))$.
    52 The fields have elements of $M_i$ labeling 
    51 The fields have elements of $M_i$ labeling 
    53 the fixed points $p_i$ and elements of $C$ labeling other (variable) points.
    52 the fixed points $p_i$ and elements of $C$ labeling other (variable) points.
    77 \begin{lem}
    76 \begin{lem}
    78 \label{lem:module-blob}%
    77 \label{lem:module-blob}%
    79 The complex $K_*(C)$ (here $C$ is being thought of as a
    78 The complex $K_*(C)$ (here $C$ is being thought of as a
    80 $C$-$C$-bimodule, not a category) is homotopy equivalent to the blob complex
    79 $C$-$C$-bimodule, not a category) is homotopy equivalent to the blob complex
    81 $\bc_*(S^1; C)$.
    80 $\bc_*(S^1; C)$.
    82 (Proof later.)
       
    83 \end{lem}
    81 \end{lem}
       
    82 The proof appears below.
    84 
    83 
    85 Next, we show that for any $C$-$C$-bimodule $M$,
    84 Next, we show that for any $C$-$C$-bimodule $M$,
    86 \begin{prop} \label{prop:hoch}
    85 \begin{prop} \label{prop:hoch}
    87 The complex $K_*(M)$ is homotopy equivalent to $\HC_*(M)$, the usual
    86 The complex $K_*(M)$ is homotopy equivalent to $\HC_*(M)$, the usual
    88 Hochschild complex of $M$.
    87 Hochschild complex of $M$.
   247 
   246 
   248 It is not hard to show that on $L_*^\ep$
   247 It is not hard to show that on $L_*^\ep$
   249 \[
   248 \[
   250 	\bd j_\ep  + j_\ep \bd = \id - i \circ s .
   249 	\bd j_\ep  + j_\ep \bd = \id - i \circ s .
   251 \]
   250 \]
   252 \nn{need to check signs coming from blob complex differential}
   251 (To get the signs correct here, we add $N_\ep$ as the first blob.)
   253 Since for $\ep$ small enough $L_*^\ep$ captures all of the
   252 Since for $\ep$ small enough $L_*^\ep$ captures all of the
   254 homology of $\bc_*(S^1)$, 
   253 homology of $\bc_*(S^1)$, 
   255 it follows that the mapping cone of $i \circ s$ is acyclic and therefore (using the fact that
   254 it follows that the mapping cone of $i \circ s$ is acyclic and therefore (using the fact that
   256 these complexes are free) $i \circ s$ is homotopic to the identity.
   255 these complexes are free) $i \circ s$ is homotopic to the identity.
   257 \end{proof}
   256 \end{proof}
   286 for some $\widetilde{e_i} \in K$, and $\sum_i a_i \tensor e_i \tensor b_i = \hat{f}(\sum_i a_i \tensor \widetilde{e_i} \tensor b_i)$.
   285 for some $\widetilde{e_i} \in K$, and $\sum_i a_i \tensor e_i \tensor b_i = \hat{f}(\sum_i a_i \tensor \widetilde{e_i} \tensor b_i)$.
   287 Finally, the interesting step is in checking that any $q = \sum_i a_i \tensor q_i \tensor b_i$ 
   286 Finally, the interesting step is in checking that any $q = \sum_i a_i \tensor q_i \tensor b_i$ 
   288 such that $\sum_i a_i q_i b_i = 0$ is in the image of $\ker(C \tensor E \tensor C \to C)$ under $\hat{g}$.
   287 such that $\sum_i a_i q_i b_i = 0$ is in the image of $\ker(C \tensor E \tensor C \to C)$ under $\hat{g}$.
   289 For each $i$, we can find $\widetilde{q_i}$ so $g(\widetilde{q_i}) = q_i$.
   288 For each $i$, we can find $\widetilde{q_i}$ so $g(\widetilde{q_i}) = q_i$.
   290 However $\sum_i a_i \widetilde{q_i} b_i$ need not be zero.
   289 However $\sum_i a_i \widetilde{q_i} b_i$ need not be zero.
   291 Consider then $$\widetilde{q} = \sum_i (a_i \tensor \widetilde{q_i} \tensor b_i) - 1 \tensor (\sum_i a_i \widetilde{q_i} b_i) \tensor 1.$$ Certainly
   290 Consider then $$\widetilde{q} = \sum_i \left(a_i \tensor \widetilde{q_i} \tensor b_i\right) - 1 \tensor \left(\sum_i a_i \widetilde{q_i} b_i\right) \tensor 1.$$ Certainly
   292 $\widetilde{q} \in \ker(C \tensor E \tensor C \to E)$.
   291 $\widetilde{q} \in \ker(C \tensor E \tensor C \to E)$.
   293 Further,
   292 Further,
   294 \begin{align*}
   293 \begin{align*}
   295 \hat{g}(\widetilde{q}) & = \sum_i (a_i \tensor g(\widetilde{q_i}) \tensor b_i) - 1 \tensor (\sum_i a_i g(\widetilde{q_i}) b_i) \tensor 1 \\
   294 \hat{g}(\widetilde{q}) & = \sum_i \left(a_i \tensor g(\widetilde{q_i}) \tensor b_i\right) - 1 \tensor \left(\sum_i a_i g(\widetilde{q_i}\right) b_i) \tensor 1 \\
   296                        & = q - 0
   295                        & = q - 0
   297 \end{align*}
   296 \end{align*}
   298 (here we used that $g$ is a map of $C$-$C$ bimodules, and that $\sum_i a_i q_i b_i = 0$).
   297 (here we used that $g$ is a map of $C$-$C$ bimodules, and that $\sum_i a_i q_i b_i = 0$).
   299 
   298 
   300 Similar arguments show that the functors
   299 Similar arguments show that the functors
   418 If $*$ is contained in a twig blob $B$ with label $u = \sum z_i$, $j_\ep(x)$ is obtained as follows.
   417 If $*$ is contained in a twig blob $B$ with label $u = \sum z_i$, $j_\ep(x)$ is obtained as follows.
   419 Let $y_i$ be the restriction of $z_i$ to $N_\ep$.
   418 Let $y_i$ be the restriction of $z_i$ to $N_\ep$.
   420 Let $x_i$ be equal to $x$ outside of $B$, equal to $z_i$ on $B \setmin N_\ep$,
   419 Let $x_i$ be equal to $x$ outside of $B$, equal to $z_i$ on $B \setmin N_\ep$,
   421 and have an additional blob $N_\ep$ with label $y_i - s_\ep(y_i)$.
   420 and have an additional blob $N_\ep$ with label $y_i - s_\ep(y_i)$.
   422 Define $j_\ep(x) = \sum x_i$.
   421 Define $j_\ep(x) = \sum x_i$.
   423 \nn{need to check signs coming from blob complex differential}
       
   424 Note that if $x \in K'_* \cap K_*^\ep$ then $j_\ep(x) \in K'_*$ also.
   422 Note that if $x \in K'_* \cap K_*^\ep$ then $j_\ep(x) \in K'_*$ also.
   425 
   423 
   426 The key property of $j_\ep$ is
   424 The key property of $j_\ep$ is
   427 \eq{
   425 \eq{
   428     \bd j_\ep + j_\ep \bd = \id - \sigma_\ep.
   426     \bd j_\ep + j_\ep \bd = \id - \sigma_\ep.
   429 }
   427 }
       
   428 (Again, to get the correct signs, $N_\ep$ must be added as the first blob.)
   430 If $j_\ep$ were defined on all of $K_*(C\otimes C)$, this would show that $\sigma_\ep$
   429 If $j_\ep$ were defined on all of $K_*(C\otimes C)$, this would show that $\sigma_\ep$
   431 is a homotopy inverse to the inclusion $K'_* \to K_*(C\otimes C)$.
   430 is a homotopy inverse to the inclusion $K'_* \to K_*(C\otimes C)$.
   432 One strategy would be to try to stitch together various $j_\ep$ for progressively smaller
   431 One strategy would be to try to stitch together various $j_\ep$ for progressively smaller
   433 $\ep$ and show that $K'_*$ is homotopy equivalent to $K_*(C\otimes C)$.
   432 $\ep$ and show that $K'_*$ is homotopy equivalent to $K_*(C\otimes C)$.
   434 Instead, we'll be less ambitious and just show that
   433 Instead, we'll be less ambitious and just show that
   529 with
   528 with
   530 \eqar{
   529 \eqar{
   531 	\bd(m\otimes a)  & = & ma - am \\
   530 	\bd(m\otimes a)  & = & ma - am \\
   532 	\bd(m\otimes a \otimes b) & = & ma\otimes b - m\otimes ab + bm \otimes a .
   531 	\bd(m\otimes a \otimes b) & = & ma\otimes b - m\otimes ab + bm \otimes a .
   533 }
   532 }
   534 In degree 0, we send $m\in M$ to the 0-blob diagram $\mathfig{0.05}{hochschild/0-chains}$; the base point
   533 In degree 0, we send $m\in M$ to the 0-blob diagram $\mathfig{0.04}{hochschild/0-chains}$; the base point
   535 in $S^1$ is labeled by $m$ and there are no other labeled points.
   534 in $S^1$ is labeled by $m$ and there are no other labeled points.
   536 In degree 1, we send $m\ot a$ to the sum of two 1-blob diagrams
   535 In degree 1, we send $m\ot a$ to the sum of two 1-blob diagrams
   537 as shown in Figure \ref{fig:hochschild-1-chains}.
   536 as shown in Figure \ref{fig:hochschild-1-chains}.
   538 
   537 
   539 \begin{figure}[t]
   538 \begin{figure}[ht]
   540 \begin{equation*}
   539 \begin{equation*}
   541 \mathfig{0.4}{hochschild/1-chains}
   540 \mathfig{0.4}{hochschild/1-chains}
   542 \end{equation*}
   541 \end{equation*}
   543 \begin{align*}
   542 \begin{align*}
   544 u_1 & = \mathfig{0.05}{hochschild/u_1-1} - \mathfig{0.05}{hochschild/u_1-2} & u_2 & = \mathfig{0.05}{hochschild/u_2-1} - \mathfig{0.05}{hochschild/u_2-2} 
   543 u_1 & = \mathfig{0.05}{hochschild/u_1-1} - \mathfig{0.05}{hochschild/u_1-2} & u_2 & = \mathfig{0.05}{hochschild/u_2-1} - \mathfig{0.05}{hochschild/u_2-2} 
   545 \end{align*}
   544 \end{align*}
   546 \caption{The image of $m \tensor a$ in the blob complex.}
   545 \caption{The image of $m \tensor a$ in the blob complex.}
   547 \label{fig:hochschild-1-chains}
   546 \label{fig:hochschild-1-chains}
   548 \end{figure}
   547 \end{figure}
   549 
   548 
   550 \begin{figure}[t]
   549 \begin{figure}[ht]
   551 \begin{equation*}
   550 \begin{equation*}
   552 \mathfig{0.6}{hochschild/2-chains-0}
   551 \mathfig{0.6}{hochschild/2-chains-0}
   553 \end{equation*}
   552 \end{equation*}
       
   553 \caption{The 0-chains in the image of $m \tensor a \tensor b$.}
       
   554 \label{fig:hochschild-2-chains-0}
       
   555 \end{figure}
       
   556 \begin{figure}[ht]
   554 \begin{equation*}
   557 \begin{equation*}
   555 \mathfig{0.4}{hochschild/2-chains-1} \qquad \mathfig{0.4}{hochschild/2-chains-2}
   558 \mathfig{0.4}{hochschild/2-chains-1} \qquad \mathfig{0.4}{hochschild/2-chains-2}
   556 \end{equation*}
   559 \end{equation*}
   557 \caption{The 0-, 1- and 2-chains in the image of $m \tensor a \tensor b$.
   560 \caption{The 1- and 2-chains in the image of $m \tensor a \tensor b$.
   558 Only the supports of the 1- and 2-blobs are shown.}
   561 Only the supports of the blobs are shown, but see Figure \ref{fig:hochschild-example-2-cell} for an example of a $2$-cell label.}
   559 \label{fig:hochschild-2-chains}
   562 \label{fig:hochschild-2-chains-12}
   560 \end{figure}
   563 \end{figure}
   561 
   564 
   562 \begin{figure}[t]
   565 \begin{figure}[ht]
   563 \begin{equation*}
   566 \begin{equation*}
   564 A = \mathfig{0.1}{hochschild/v_1} + \mathfig{0.1}{hochschild/v_2} + \mathfig{0.1}{hochschild/v_3} + \mathfig{0.1}{hochschild/v_4}
   567 A = \mathfig{0.1}{hochschild/v_1} + \mathfig{0.1}{hochschild/v_2} + \mathfig{0.1}{hochschild/v_3} + \mathfig{0.1}{hochschild/v_4}
   565 \end{equation*}
   568 \end{equation*}
   566 \begin{align*}
   569 \begin{align*}
   567 v_1 & = \mathfig{0.05}{hochschild/v_1-1} -  \mathfig{0.05}{hochschild/v_1-2} &  v_2 & = \mathfig{0.05}{hochschild/v_2-1} -  \mathfig{0.05}{hochschild/v_2-2} \\ 
   570 v_1 & = \mathfig{0.05}{hochschild/v_1-1} -  \mathfig{0.05}{hochschild/v_1-2} &  v_2 & = \mathfig{0.05}{hochschild/v_2-1} -  \mathfig{0.05}{hochschild/v_2-2} \\ 
   568 v_3 & = \mathfig{0.05}{hochschild/v_3-1} -  \mathfig{0.05}{hochschild/v_3-2} &  v_4 & = \mathfig{0.05}{hochschild/v_4-1} -  \mathfig{0.05}{hochschild/v_4-2}
   571 v_3 & = \mathfig{0.05}{hochschild/v_3-1} -  \mathfig{0.05}{hochschild/v_3-2} &  v_4 & = \mathfig{0.05}{hochschild/v_4-1} -  \mathfig{0.05}{hochschild/v_4-2}
   569 \end{align*}
   572 \end{align*}
   570 \caption{One of the 2-cells from Figure \ref{fig:hochschild-2-chains}.}
   573 \caption{One of the 2-cells from Figure \ref{fig:hochschild-2-chains-12}.}
   571 \label{fig:hochschild-example-2-cell}
   574 \label{fig:hochschild-example-2-cell}
   572 \end{figure}
   575 \end{figure}
   573 
   576 
   574 In degree 2, we send $m\ot a \ot b$ to the sum of 24 ($=6\cdot4$) 2-blob diagrams as shown in
   577 In degree 2, we send $m\ot a \ot b$ to the sum of 24 ($=6\cdot4$) 2-blob diagrams as shown in
   575 Figure \ref{fig:hochschild-2-chains}.
   578 Figures \ref{fig:hochschild-2-chains-0} and \ref{fig:hochschild-2-chains-12}.
   576 In Figure \ref{fig:hochschild-2-chains} the 1- and 2-blob diagrams are indicated only by their support.
   579 In Figure \ref{fig:hochschild-2-chains-12} the 1- and 2-blob diagrams are indicated only by their support.
   577 We leave it to the reader to determine the labels of the 1-blob diagrams.
   580 We leave it to the reader to determine the labels of the 1-blob diagrams.
   578 Each 2-cell in the figure is labeled by a ball $V$ in $S^1$ which contains the support of all
   581 Each 2-cell in the figure is labeled by a ball $V$ in $S^1$ which contains the support of all
   579 1-blob diagrams in its boundary.
   582 1-blob diagrams in its boundary.
   580 Such a 2-cell corresponds to a sum of the 2-blob diagrams obtained by adding $V$
   583 Such a 2-cell corresponds to a sum of the 2-blob diagrams obtained by adding $V$
   581 as an outer (non-twig) blob to each of the 1-blob diagrams in the boundary of the 2-cell.
   584 as an outer (non-twig) blob to each of the 1-blob diagrams in the boundary of the 2-cell.
   582 Figure \ref{fig:hochschild-example-2-cell} shows this explicitly for the 2-cell
   585 Figure \ref{fig:hochschild-example-2-cell} shows this explicitly for the 2-cell
   583 labeled $A$ in Figure \ref{fig:hochschild-2-chains}.
   586 labeled $A$ in Figure \ref{fig:hochschild-2-chains-12}.
   584 Note that the (blob complex) boundary of this sum of 2-blob diagrams is
   587 Note that the (blob complex) boundary of this sum of 2-blob diagrams is
   585 precisely the sum of the 1-blob diagrams corresponding to the boundary of the 2-cell.
   588 precisely the sum of the 1-blob diagrams corresponding to the boundary of the 2-cell.
   586 (Compare with the proof of \ref{bcontract}.)
   589 (Compare with the proof of \ref{bcontract}.)